5x^2=204

Solution for 5x^2=204 equation:

5x^2=204

We move all terms to the left:

5x^2-(204)=0

a = 5; b = 0; c = -204;
Δ = b2-4ac
Δ = 02-4·5·(-204)
Δ = 4080
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4080}=\sqrt{16*255}=\sqrt{16}*\sqrt{255}=4\sqrt{255}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{255}}{2*5}=\frac{0-4\sqrt{255}}{10}
=-\frac{4\sqrt{255}}{10}
=-\frac{2\sqrt{255}}{5}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{255}}{2*5}=\frac{0+4\sqrt{255}}{10}
=\frac{4\sqrt{255}}{10}
=\frac{2\sqrt{255}}{5}
$